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21p^2-27p+6=0
a = 21; b = -27; c = +6;
Δ = b2-4ac
Δ = -272-4·21·6
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-15}{2*21}=\frac{12}{42} =2/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+15}{2*21}=\frac{42}{42} =1 $
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